2x^2-57x+106=0

Solution for 2x^2-57x+106=0 equation:

2x^2-57x+106=0

a = 2; b = -57; c = +106;
Δ = b2-4ac
Δ = -572-4·2·106
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-49}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+49}{2*2}=\frac{106}{4}
=26+1/2
$